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5(x^2)=200
We move all terms to the left:
5(x^2)-(200)=0
a = 5; b = 0; c = -200;
Δ = b2-4ac
Δ = 02-4·5·(-200)
Δ = 4000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{4000}=\sqrt{400*10}=\sqrt{400}*\sqrt{10}=20\sqrt{10}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-20\sqrt{10}}{2*5}=\frac{0-20\sqrt{10}}{10} =-\frac{20\sqrt{10}}{10} =-2\sqrt{10} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+20\sqrt{10}}{2*5}=\frac{0+20\sqrt{10}}{10} =\frac{20\sqrt{10}}{10} =2\sqrt{10} $
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